1 条题解
-
0
C++ :
#include <iostream> #include <cmath> using namespace std; int main(){ int ch[1001], ma[1001], en[1001], n; cin >> n; for(int i = 0; i < n; ++i){ cin >> ch[i] >> ma[i] >> en[i]; } int cnt = 0; for(int i = 0; i < n; ++i){ int c1 = ch[i]; int m1 = ma[i]; int e1 = en[i]; int t1 = c1 + m1 + e1; for(int j = i + 1; j < n; ++j){ int c2 = ch[j]; int m2 = ma[j]; int e2 = en[j]; int t2 = c2 + m2 + e2; if(abs(c1 - c2) <= 5 && abs(m1 - m2) <= 5 && abs(e1 - e2) <= 5 && abs(t1 - t2) <= 10){ cnt++; } } } cout << cnt << endl; return 0; }
- 1
信息
- ID
- 68
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者